\(\frac{5}{10}+\frac{12}{6}:\frac{11}{12}.\left(-12\right)\)
Những câu hỏi liên quan
b) \(\frac{-5}{12}.\frac{2}{11}+\frac{-5}{12}.\frac{9}{11}+\frac{5}{12}\)
c) \(6\frac{9}{10}+\left(\frac{2}{5}-\frac{1}{10}\right)\)
b)-5/12 . 2/11+(-5/12) . 9/11+5/12
=(-5/12+5/12).(2/11+9/11)
=0.1=0
c)6/9/10+(2/5-1/10)
=69/10+3/10
=36/5
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\(b)\)\(\frac{-5}{12}.\frac{2}{11}+\frac{-5}{12}.\frac{9}{11}+\frac{5}{12}\)
\(=\frac{-5}{12}.\frac{2}{11}+\frac{-5}{12}.\frac{9}{11}+\frac{5}{12}.1\)
\(=\frac{-5}{12}.\left(\frac{2}{11}+\frac{9}{11}+1\right)\)
\(=\frac{-5}{12}.2\)
\(=\frac{-5}{6}\)
\(c)\)\(6\frac{9}{10}+\left(\frac{2}{5}-\frac{1}{10}\right)\)
\(=6\frac{9}{10}+\frac{2}{5}-\frac{1}{10}\)
\(=\left(6\frac{9}{10}-\frac{1}{10}\right)+\frac{2}{5}\)
\(=6\frac{4}{5}+\frac{2}{5}\)
\(=6\frac{6}{5}=7\frac{1}{5}\)
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1 , \(c=\frac{10\frac{1}{3}.\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}.\left(\frac{10}{3}-1,75\right)}{\frac{5}{\left(91-0,25\right).\frac{60}{11}-1}}\)
2 , \(A=\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,265+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
cac ban giai nhanh giup minh nha! ai nhanh minh k!
Tính
\(a,\frac{5}{6}+6\frac{5}{6}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(b,1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
Tớ ko bít phải làm sao bây giờ ?
tô ? ko ? bít ?
-_-! ai thick tích cu !
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mk chỉ tính đc kết quả phần a) thôi..
a, = 5
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Xem thêm câu trả lời
\(a.A=[\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}]+\frac{1890}{2005}+115\)
b.B=\(\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\cdot\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(42-5\frac{1}{3}\right)}\cdot\left(-1\frac{19}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
\(A=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{-5\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}+\frac{3\left(0,5+\frac{1}{3}-0,25\right)}{5\left(0,5+\frac{1}{3}-0,25\right)}=-\frac{3}{5}+\frac{3}{5}=0\)
sao bạn tự đăng tự giải thế? hay là bạn giải cho ai à?
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So sánh A và B , biết rằng:Asqrt[13]{12timesleft(11-frac{frac{left(10times8right)^{left(9+8right)}}{8}+frac{6^7times6-6}{6}}{frac{5}{4}}right)div3+2}Bsqrt[13]{12divleft(11+frac{frac{left(10times8right)^{left(9-8right)}}{8}+frac{6^7times6+6}{6}}{frac{5}{4}}right)times3-2}
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So sánh \(A\) và \(B\) , biết rằng:
\(A=\sqrt[13]{12\times\left(11-\frac{\frac{\left(10\times8\right)^{\left(9+8\right)}}{8}+\frac{6^7\times6-6}{6}}{\frac{5}{4}}\right)\div3+2}\)
\(B=\sqrt[13]{12\div\left(11+\frac{\frac{\left(10\times8\right)^{\left(9-8\right)}}{8}+\frac{6^7\times6+6}{6}}{\frac{5}{4}}\right)\times3-2}\)
\(\frac{10\frac{1}{3}.\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}\left(\frac{10}{3}-1.75\right)}{\frac{5}{\left(91-0.25\right).\frac{60}{11}-1}}\)
\(\frac{10\frac{1}{3}\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}\left(\frac{10}{3}-1,75\right)}{\frac{5}{\left(91-0,25\right).\frac{60}{11}-1}}\)
\(\Leftrightarrow\left(\frac{31}{3}.\frac{25}{21}-\frac{12}{11}.\frac{19}{12}\right):\left(5:495-1\right)\)
\(\Leftrightarrow\left(\frac{775}{63}-\frac{19}{11}\right):\left(-\frac{98}{99}\right)\)
\(\Leftrightarrow x=-\frac{3664}{343}\)
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Tính : \(A=\frac{10\frac{1}{3}\left(26\frac{1}{3}-\frac{176}{7}\right)-\frac{12}{11}\left(\frac{10}{3}-1,75\right)}{\frac{5}{\left(91-0,25\right).\frac{60}{11}-1}}\)
mk ko viết lại đề đâu
A=\(\frac{\frac{31}{3}.\frac{25}{21}-\frac{12}{11}.\frac{19}{12}}{\frac{5}{90,75.\frac{60}{11}-1}}=\frac{\frac{775}{63}-\frac{19}{11}}{\frac{5}{495-1}}=\frac{7328}{693}:\frac{5}{494}=\frac{7328}{693}.\frac{494}{5}=\)
có máy tính thì tính được hết
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Bài 1:
a)frac{5}{6}-frac{2}{3}+frac{1}{4} b)1frac{11}{12}-frac{5}{12}cdotleft(frac{4}{5}-frac{1}{10}right):frac{-5}{12}
Bài 2:
a) frac{1}{2}cdot x-frac{2}{5}frac{1}{5} b)left(1-2cdot xright)cdotfrac{4}{3}left(-2right)^3
Đọc tiếp
Bài 1:
a)\(\frac{5}{6}\)-\(\frac{2}{3}+\frac{1}{4}\) b)\(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\)
Bài 2:
a) \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\) b)\(\left(1-2\cdot x\right)\cdot\frac{4}{3}=\left(-2\right)^3\)
Bài 1:
a) Ta có: \(\frac{5}{6}-\frac{2}{3}+\frac{1}{4}\)
\(=\frac{10}{12}-\frac{8}{12}+\frac{3}{12}\)
\(=\frac{2+3}{12}=\frac{5}{12}\)
b) Ta có: \(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\)
\(=\frac{23}{12}-\frac{5}{12}\cdot\left(\frac{8}{10}-\frac{1}{10}\right)\cdot\frac{-12}{5}\)
\(=\frac{23}{12}-\frac{5}{12}\cdot\frac{7}{10}\cdot\frac{-12}{5}\)
\(=\frac{23}{12}-\frac{-7}{10}\)
\(=\frac{115}{60}+\frac{42}{60}=\frac{157}{60}\)
Bài 2:
a) Ta có: \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\)
\(\Leftrightarrow\frac{1}{2}\cdot x=\frac{1}{5}+\frac{2}{5}=\frac{3}{5}\)
\(\Leftrightarrow x=\frac{3}{5}:\frac{1}{2}=\frac{3}{5}\cdot2=\frac{6}{5}\)
Vậy: \(x=\frac{6}{5}\)
b) Ta có: \(\left(1-2x\right)\cdot\frac{4}{3}=\left(-2\right)^3\)
\(\Leftrightarrow\left(1-2x\right)\cdot\frac{4}{3}=-8\)
\(\Leftrightarrow1-2x=-8:\frac{4}{3}=-8\cdot\frac{3}{4}=-6\)
\(\Leftrightarrow-2x=-6-1=-7\)
hay \(x=\frac{7}{2}\)
Vậy: \(x=\frac{7}{2}\)
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Bài 1:
a) Ta có: 56−23+1456−23+14
=1012−812+312=1012−812+312
=2+312=512=2+312=512
b) Ta có: 11112−512⋅(45−110):−51211112−512⋅(45−110):−512
=2312−512⋅(810−110)⋅−125=2312−512⋅(810−110)⋅−125
=2312−512⋅710⋅−125=2312−512⋅710⋅−125
=2312−−710=2312−−710
=11560+4260=15760=11560+4260=15760
Bài 2:
a) Ta có: 12⋅x−25=1512⋅x−25=15
⇔12⋅x=15+25=35⇔12⋅x=15+25=35
⇔x=35:12=35⋅2=65⇔x=35:12=35⋅2=65
Vậy: x=65x=65
b) Ta có: (1−2x)⋅43=(−2)3(1−2x)⋅43=(−2)3
⇔(1−2x)⋅43=−8⇔(1−2x)⋅43=−8
⇔1−2x=−8:43=−8⋅34=−6⇔1−2x=−8:43=−8⋅34=−6
⇔−2x=−6−1=−7⇔−2x=−6−1=−7
hay x=72x=72
Vậy: x=72
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