\(25\).\(5^x\) = \(5^5\)
 \(5^2\) .  \(5^x\) = \(5^5\)

             \(5^x\) = \(5^5\) : \(5^2\)

                ^{\(5^x\)} = \(5^3\) 

vậy x = 3

25.5^x=5⁵

25.5^x=125

     5^x=125/25

      5^x=5

 mà 5=5¹

=> 5^x=5¹

   => x=1

sai rồi bn zì ơi

2^x . 2⁶ . 2⁴ = 2³ . 2⁶⁰

2^{x + 6 + 4} = 2^{3 + 60}

2^{x + 10} = 2⁶³

=> x + 10 = 63

x = 63 - 10 

x = 53

a/ 5^x.5².5³=5².5⁴⁰

5^x.5⁵=5⁴²

5^x=5³⁷

x=37

b/ 2^x.2⁶.2⁴=2³.2⁶⁰

2^x.2¹⁰=2⁶³

2^x=2⁵³

x=53

(5 mũ 2)mũ 3 : 5 mũ 2

5 mũ 2 x3 :5 mũ 2

5 mũ 6 : 5 mũ 2 =5 mũ 4=625

ok nha bạn

5²⁵.5^x-1=5²⁵

      5^x-1=5²⁵:5²⁵

      5^x-1= 5⁰

    =>x-1=0

         x=0+1

         x=1

vậy x=1

\(5^{25}.5^{x-1}=5^{25}\\ 5^{x-1}=5^{25}:5^{25}\\ 5^{x-1}=1\\ 5^{x-1}=5^0\\ x-1=0\\ x=0+1\\ x=1\)

\(\)

a) \(x-1\frac{4}{5}=\frac{10}{5}\)

\(\Rightarrow x=2+1\frac{4}{5}=3\frac{4}{5}=\frac{19}{5}\)

b) \(5,85:x=26-25,5\)

\(\Leftrightarrow5,85:x=0,5\)

\(\Rightarrow x=5,85:0,5=11,7\)

c) \(151-\left(-2\right).\left(x-6\right)=2227:17=131\)

\(\Rightarrow\left(-2\right).\left(x-6\right)=151-131=20\)

\(\Rightarrow\left(x-6\right)=20:\left(-2\right)=-10\)

\(\Rightarrow x=-4\)

d) \(\frac{2}{3}-\frac{1}{3}x=\frac{1}{4}\)

\(\Rightarrow \frac{1}{3}x=\frac{2}{3}-\frac{1}{4}=\frac{5}{12}\)

\(\Rightarrow x=\frac{5}{12}:\frac{1}{3}=\frac{5}{4}\)

dấu chấm (.) là dấu nhân nhé

Ban co chac ket qua dung ko

5². 5^{X+ 2}= 5³. 5³

5². 5^{X+ 2}= 5⁶

5^{X+ 2}= 5⁶: 5²

5^X+2= 5⁴

=> X+ 2= 4

X= 4- 2

X=2

đề bài ko rõ

\(20\%\times25,5+\dfrac{1}{5}\times15,5+0,2\times59\)

\(=\dfrac{1}{5}\times25,5+\dfrac{1}{5}\times15,5+\dfrac{1}{5}\times59\)

\(=\dfrac{1}{5}\times\left(25,5+15,5+59\right)\)

\(=\dfrac{1}{5}\times100\)

\(=20\)

Giải:

a) \(25.5^{x+5}=5^8\)

\(\Leftrightarrow5^2.5^{x+5}=5^8\)

\(\Leftrightarrow5^{x+7}=5^8\)

\(\Leftrightarrow x+7=8\)

\(\Leftrightarrow x=1\)

Vậy ...

b) \(124+\dfrac{225}{\left(x-3\right)^2}=57\)

\(\Leftrightarrow\dfrac{15^2}{\left(x-3\right)^2}=-67\)

\(\Leftrightarrow\left(\dfrac{15}{x-3}\right)^2=-67\)

Mà \(\left(\dfrac{15}{x-3}\right)^2\ge0,\forall x\left(x\ne3\right)\)

Suy ra không có x thỏa mãn

Vậy ...