bạn ơi \(3x\frac{3}{10}\) hay  \(\frac{3x3}{10}\)

mẫu là 2 * 5 ; 5 * 8 ; 8 * 11 ..............và cái mẫu cuối sai sai

bạn Lê Dạ Quỳnh nói đúng đó

\(\frac{1}{5}+\frac{1}{7}+\frac{1}{3}+\frac{100}{125}+\frac{66}{77}+\frac{40}{60}\)

\(=\frac{1}{5}+\frac{1}{7}+\frac{1}{3}+\frac{4}{5}+\frac{6}{7}+\frac{2}{3}\)

\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+\left(\frac{1}{3}+\frac{2}{3}\right)\)

\(=1+1+1\)

\(=3\)

mk tạo cơ hội kiếm điểm nè

lung tung dã man bài toán này bịa

bài này đến cả giáo viên con không nghĩ ra nói gì tụi này

hại não qá bà con ơi 

Bài 1:

a) x - 32 + 25 = 12 x 2

    x- 32  +25 = 24

    x -32         = -1

    x               = 31

b) 24 + x - 3 = 21

   24+x         = 24

        x          = 0

c) x * 10 : 2 = 40

    x *10       = 80

    x             = 8

Bài 2:

a) 123 - 82 x 6= 123- 492= -369

b) 458 - 125 + 23= 333+23 = 356

c) 325 + 125 x 125 x 325= 325 + 5 078 450

 Cái này giống như bài lớp 6 ý.

Bài 1 : Tìm x

a) x - 32 + 25 = 12 x 2

    x - 32 + 25 = 24

    x - 32         = 24 - 25

     x - 32        = ( - 1 )

      x             = ( -1 ) + 32

      x           = 31

b) 24 + x - 3 = 21

   24 + x       = 21 + 3

   24 + x       = 24

           x       = 24 - 24

           x        = 0

c) x * 10 : 2 = 40

    x * 10      = 40 x 2

    x * 10      = 80

    x             = 80 : 10

    x             = 8

Bài 2: Tính giá trị của biểu thức 

a) 123 - 82 x 6

    123 - 492

    -369

b) 458 - 125 + 23

   333 + 23

   356

c) 325 + 125 x 125 x 325

    325 + 5078125

    5078450

Bài 1:

a/\(x-32+25=12\cdot2\)

\(x-32+25=24\)

\(x-32=24-25=-1\)

\(x=\left(-1\right)+32=31\)

b/\(24+x-3=21\)

\(24+x=21+3=24\)

\(x=24-24=0\)

c/\(\frac{x\cdot10}{2}=40\)

\(x\cdot10=40\cdot2=80\)

\(x=\frac{80}{10}=8\)

4177

13400

3400

5200

4000

4177

13400

3400

5200

4000

29 . 87 - 29 . 23 + 64. 71 = 6400

1.

a) \(125+80+375+220\)

\(=\left(125+375\right)+\left(80+220\right)\)

\(=500+300\)

\(=800\)

b) \(25.11.8.4.125\)

\(=\left(25.4\right).\left(8.125\right).11\)

\(=100.1000.11\)

\(=1100000\)

c) \(18.74+18.27-18\)

\(=18.\left(74+27-1\right)\)

\(=18.100\)

\(=1800\)

d) \(75.23+75.77-500\)

\(=75.\left(23+77\right)-500\)

\(=75.100-500\)

\(=7500-500\)

\(=7000\)

e) \(150:\left[25.\left(18-4^2\right)\right]\)

\(=150:\left[25.\left(18-16\right)\right]\)

\(=150:\left[25.2\right]\)

\(=150:50\)

\(=3\)

f) \(125.23.2.8.50\)

\(=\left(125.8\right).\left(2.50\right).23\)

\(=1000.100.23\)

\(=2300000\)

g) \(235+88+165+12\)

\(=\left(235+165\right)+\left(88+12\right)\)

\(=400+100\)

\(=500\)

h) \(71.32+71.68-1100\)

\(=71.\left(32+68\right)-1100\)

\(=71.100-1100\)

\(=7100-1100\)

\(=6000\)

i) \(6^7:6^6+4^3.2-24^0\)

\(=6+64.2-1\)

\(=6+128-1\)

\(=133\)

j) \(546-6.\left[158:\left(30+7^2\right)\right]\)

\(=546-6.\left[158:\left(30+49\right)\right]\)

\(=546-6.\left[158:79\right]\)

\(=546-6.2\)

\(=546-12\)

\(=534\)

k) \(268+147+132+253\)

\(=\left(268+132\right)+\left(147+253\right)\)

\(=400+400\)

\(=800\)

2. 

a) \(7x=707\)

\(x=707:7\)

\(x=101\)

b) \(6x+5=47\)

\(6x=47-5\)

\(6x=42\)

\(x=42:6\)

\(x=7\)

c) \(35:\left(x+1\right)=7\)

\(x+1=35:7\)

\(x+1=5\)

\(x=5-1\)

\(x=4\)

d) \(12+\left(29-3x\right)=35\)

\(29-3x=35-12\)

\(29-3x=23\)

\(3x=29-23\)

\(3x=6\)

\(x=6:3\)

\(x=2\)

e) \(2.4^x+10^1=138\)

\(2.4^x=138-10\)

\(2.4^x=128\)

\(4^x=128:2\)

\(4^x=64=4^3\)

\(\Rightarrow x=3\)

f) \(7x=140\)

\(x=140:7\)

\(x=20\)

g) \(7\left(15-x\right)+14=84\)

\(7\left(15-x\right)=84-14\)

\(7\left(15-x\right)=70\)

\(15-x=70:7\)

\(15-x=10\)

\(x=15-10\)

\(x=5\)

h) \(3^x.5-15=390\)

\(3^x.5=390+15\)

\(3^x.5=405\)

\(3^x=405:5\)

\(3^x=81=3^4\)

\(\Rightarrow x=4\)

3.

Ta có:

\(\Rightarrow n+11⋮n+1\)

\(\Rightarrow n+1+10⋮n+1\)

\(\Rightarrow10⋮n+1\) hay \(n+1\inƯ\left(10\right)=\left\{-10;-5;-2;-1;1;2;5;10\right\}\)

\(\Rightarrow\) \(n\in\left\{-11;-6;-3;-2;0;1;4;9\right\}\)

Vì \(n\in N\) nên \(n\in\left\{0;1;4;9\right\}\)

a) 27.77+24.27-27

= 27.77+24.27-27.1

= 27.(77+24-1)

=27.

40 : 23 = \(\dfrac{40}{23}\)

40:23=1,739130434782609

40/23