y=2/1.3 + 2/3.5 +2/5.7 +...+2/99.101
y= 1.(1-1/3+1/3-1/5+1/5-1/7+....+1/99-1/101)
y=1. ( 1-1/101)
y= 1. 100/101
y=100/101
y=2/1.3 + 2/3.5 +2/5.7 +...+2/99.101
y= 1.(1-1/3+1/3-1/5+1/5-1/7+....+1/99-1/101)
y=1. ( 1-1/101)
y= 1. 100/101
y=100/101
Tính tổng:
a,\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b,\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
a)\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b) \(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
( Tính tổng )
Tính a) \(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b) \(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
Tính tổng a>
\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{99.101}\)
b>
\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
tinh tổng
a)\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
b)\(\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{99.101}\)
1,Tính tổng:
a,\(\frac{2}{1.3}\)+\(\frac{2}{3.5}\)+\(\frac{2}{5.7}\)+...+\(\frac{2}{99.101}\)
b,\(\frac{5}{1.3}\)+\(\frac{5}{3.5}\)+\(\frac{5}{5.7}\)+....+\(\frac{5}{99.101}\)
\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+......+\frac{2}{99.101}\) Hãy tính tổng
\(B=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{99.101}\)
Tính giá trị của biểu thức
A=1.2.3........100-1.2.3.....99-1.2.3.....99^2
B=\(\frac{\left\{3.4.2^{16}\right\}}{11.2^{13}.4^{11}-4^9.2^{18}}\)
C=1.2+2.3+3.4+...+98.99
D=\(\frac{2}{1.3}\)+\(\frac{2}{3.5}\)+\(\frac{2}{5.7}\)+....+\(\frac{2}{99.101}\)