\(x\cdot\frac{1}{3}+x\cdot\frac{2}{5}-4=3\)
\(x\cdot\left(\frac{1}{3}+\frac{2}{5}\right)-4=3\)
\(x\cdot\frac{11}{15}=7\)
\(x=\frac{105}{11}\)
\(x.\frac{1}{3}+x.\frac{2}{5}-4=3\)
\(\Rightarrow x.\left(\frac{1}{3}+\frac{2}{5}\right)=7\)
\(\Rightarrow x.\left(\frac{5}{15}+\frac{6}{15}\right)=7\)
\(\Rightarrow x.\frac{11}{15}=7\Rightarrow x=7:\frac{11}{15}=\frac{105}{11}\)
Vậy x = 105/11
x*(1/3+2/5)-4=3
=>x*(5/15+6/15)=7
=>x*11/15=7=>x=105/11
Vậy x=105/11
\(x.\frac{1}{3}+x.\frac{2}{5}-4=3\)
\(x.\left(\frac{1}{3}+\frac{2}{5}\right)=4+3\)
\(x.\frac{11}{15}=7\)
\(x=7:\frac{11}{15}\)
\(x=7.\frac{15}{11}\)
\(x=\frac{105}{11}\)
\(x.\frac{1}{3}+x.\frac{2}{5}-4=3\)
\(\Rightarrow x.\left(\frac{5}{15}+\frac{6}{15}\right)=7\)
\(\Rightarrow x.\frac{11}{15}=7\)
\(\Rightarrow x=\frac{105}{11}\)
x.(1/3+2/5)-4=3
x.11/15-4=3
x.11/15=4+3
x.11/15=7
x=7:11/15
x=105/11
15
