Question

x³+27-(x+3)(11-2x)

Answer 1

x^3+27-[11x-2x^2+33-6x]

x^3+27-11x+2x^2-33+6x

x^3+2x^2-5x-6

Answer 2

Phân tích thành nhân tử hả

\(x^3+27-\left(x+3\right)\left(11-2x\right)\)

\(=x^3+3^3-\left(x+3\right)\left(11-2x\right)\)

\(=\left(x+3\right)\left(x^2-3x+9\right)-\left(x+3\right)\left(11-2x\right)\)

\(=\left(x+3\right)\left(x^2-3x+9-11+2x\right)\)

\(=\left(x+3\right)\left(x^2-x-2\right)\)

\(=\left(x+3\right)\left(x^2-2x+x-2\right)\)

\(=\left(x+3\right)\left(x-2\right)\left(x+1\right)\)