1, \(\frac{x+1}{2}=\frac{x}{3}\)
<=> 3(x+1)=2x
<=> 3x+3-2x=0
<=> x+3=0
<=> x=-3
2, \(\frac{1-2x}{9}=\frac{1}{1-2x}\left(x\ne\frac{1}{2}\right)\)
<=> (1-2x)2=9
<=> \(\orbr{\begin{cases}1-2x=3\\1-2x=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-2\\2x=4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-1\\x=2\end{cases}}\left(tmđk\right)}\)
Vậy x={-1;2}