<=>(x+1)(1/10 + 1/11+1/12) =(x+1)(1/13 + 1/14)
<=>(x+1)(1/10 + 1/11+1/12 -1/13 -1/14)=0
<=> x+1=0(vì biểu thức 1/10 + 1/11 +1/12-1/13-1/14#0)
<=>x= -1
Tìm x biết (x+1)/10+(x+1)/11+(x+11)/12=(x+1)/13+(x+1)/14
x+1/10+x+1/11+x+1/12=x+1/13+x+1/14
x+1/10 + x+1/11 + x+1/12= x+1/13 + x+1/14
x+1/10+ x+1/11+ x+1/12+ x+1/13+ x+1/14
x+1/10+x+1/11+x+1/12=x+1/13+x+1/14
tìm x
tìm x biết : x+1/10 + x+1/11 + x+1/12 - x+1/13 + x+1/14 = 0
Tìm x biết (x+1)/10 + (x+1) /11 + (x+1)/12 = (x+1)/13 + (x+1)/14
x+1/10+x+1/11+x+1/12+x+1/13+x+1/14
\(\dfrac{x+1}{10}\)+\(\dfrac{x+1}{11}\)+\(\dfrac{x+1}{12}\)=\(\dfrac{x+1}{13}\)+\(\dfrac{x+1}{14}\)
