Question

\(x-\frac{4}{5}=\frac{4}{5}+\left[\frac{3}{7}+\frac{3}{5}\right]\)tìm x

Answer 1

\(x-\frac{4}{5}=\frac{4}{5}+\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(x-\frac{4}{5}=\frac{4}{5}+\frac{36}{35}\)

\(x-\frac{4}{5}=\frac{64}{35}\)

\(x=\frac{64}{35}+\frac{4}{5}\)

\(x=\frac{92}{35}\)

Answer 2

\(x-\frac{4}{5}=\frac{4}{5}+\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(x=\frac{4}{5}+\frac{3}{7}+\frac{3}{5}+\frac{4}{5}\)

\(x=\frac{11}{5}+\frac{3}{7}\)

\(x=\frac{11\times7+3\times5}{7\times5}\)

\(x=\frac{92}{35}\)

Answer 3

\(x=\frac{92}{35}\)

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Answer 4

\(x-\frac{4}{5}=\frac{4}{5}+\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(x-\frac{4}{5}=\frac{4}{5}+\frac{36}{35}\)

\(x-\frac{4}{5}=\frac{64}{35}\)

\(x=\frac{64}{35}-\frac{4}{5}\)

\(x=\frac{36}{35}\)