\(\frac{x-3}{3}=\frac{12}{x-3}\)
\(\Rightarrow\left(x-3\right).\left(x-3\right)=36\)
\(\Rightarrow\left(x-3\right)^2=6^2;\left(-6\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x-3=6\\x-3=-6\end{cases}}\)
\(\orbr{\begin{cases}x=9\\x=-3\end{cases}}\)
Vậy x=9;-3