\(\left(x-2019\right)^{2019}=\left(x-2019\right)^{2018}\)
\(\Leftrightarrow\left(x-2019\right)^{2019}-\left(x-2019\right)^{2018}=0\)
\(\Leftrightarrow\left(x-2019\right)^{2018}\left(x-2019-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=2019\\x=2020\end{cases}}\)
Ta có: \(\left(x-2019\right)^{2019}=\left(x-2019\right)^{2018}\)
\(\Leftrightarrow\left(x-2019\right)^{2019}-\left(x-2019\right)^{2018}=0\)
\(\Leftrightarrow\left(x-2019\right)^{2018}.\left(x-2019-1\right)=0\)
\(\Leftrightarrow\left(x-2019\right)^{2018}.\left(x-2020\right)=0\)
\(\Rightarrow\)\(x-2020=0\)Hoặc \(\left(x-2019\right)^{2018}=0\)
\( TH1:x-2020=0\Rightarrow x=2020\)
\(TH2:\left(x-2019\right)^{2018}=0\Leftrightarrow x-2019=0\Leftrightarrow x=2019\)
Vậy x= 2019 và x=2020
#Học tốt
\(\left(x-2019\right)^{2019}=\left(x-2019\right)^{2018}\)
\(\Rightarrow\left(x-2019\right)^{2019}-\left(x-2019\right)^{2018}=0\)
\(\Rightarrow\left(x-2019\right)^{2018}.\left[\left(x-2019\right)-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-2019^{2018=0}\\\left(x-2019\right)-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x-2019=0\\x-2019=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=2019\\x=2020\end{cases}}\)
Vậy x \(\in\){2019,2020} là giá trị cần tìm .
\(\left(x-2019\right)^{2019}=\left(x-2019\right)^{2018}\)
\(\Leftrightarrow\left(x-2019\right)^{2019}-\left(x-2019\right)^{2018}=0\)
\(\Leftrightarrow\left(x-2019\right)^{2018}\left(x-2020\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x-2019\right)^{2018}=0\\x-2020=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x-2019=0\\x=2020\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2019\\x=2020\end{cases}}}\)
