Question

Viết dưới dạng tích các tổng sau:

1/ ab+ ac

2/ ab - ac + ad

3/ ax - bx - cx + dx

4/ a(b + c) - d(b + c)

5/ ac - ad + bc - bd

6/ ax + by + bx + ay

Answer 1

1/ ab+ ac

=a(b+c)

2/ ab - ac + ad

=a(b-c+d)

3/ ax - bx - cx + dx

=x(a-b-c+d)

4/ a(b + c) - d(b + c)

=(a-d)(b+c)

5/ ac - ad + bc - bd

=a(c-d)+b(c-d)

=(a+b)(c-d)

6/ ax + by + bx + ay

=x(a+b)+y(b+a)

=(x+y)(b+a)

Answer 2

A) ab + ac=a.(b+c)

B)ab - ac + ad=a.(b-c+d)

C) ã-bx-cx+dx=x.(a-b-c+d)

D)a(b+c) - d(b+c)=(b+c).(a-d)

E) ac-ad+bc-bd=a.(c-d)+b.(c-d)=(c-d).(a+b)

G) ax+by+bx+ay=x.(a+b)+y.(b+a)=(a+b).((x.y)

Answer 3

1) \(ab+ac=a\left(b+c\right)\)

2) \(ab-ac+ad=a\left(b-c+d\right)\)

3) \(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

4) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

5) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+d\right)\left(c-d\right)\)

6) \(ax+by+bx+ay=x\left(a+b\right)+y\left(a+b\right)=\left(x+y\right)\left(a+b\right)\)