Question

Tính

a)\(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{999}+1\right);\)   

b)\(\left(\frac{1}{2}-1\right).\left(\frac{1}{3}-1\right).\left(\frac{1}{4}-1\right)...\left(\frac{1}{1000}-1\right)\)

c)\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{99}{10^2}\)

Answer 1

mấy bài này dễ tự làm

Answer 2

lam on ai biet thi chi trong toi nay tui se cho ma ngay mai la phai nop rui

Answer 3

   ( 1/2 + 1 ) . ( 1/3 + 1 ) . ( 1/4 + 1 ) . ... . ( 1/999 + 1 )

= 3/2 . 4/3 . 5/4 . ... . 1000/999

= 3 . 4 . 5 . ... . 1000 / 2 . 3 . 4 . ... . 999

= 500