Question

tính (x+1)/2009+(x+1)/2008+(x+1) /2007=(x+10)/2000+(x+11)/1999+(x+12)/1998

Answer 1

\(\dfrac{X+1}{2009}+\dfrac{x+2}{2008}+\dfrac{x+3}{2007}=\dfrac{x+10}{2000}+\dfrac{x+11}{1999}+\dfrac{x+12}{1998}\)

đề thế này mới đúng ngu ạ

làm nhé nhớ tick

\(\Rightarrow\dfrac{x+2010}{2009}+\dfrac{x+2010}{2008}+\dfrac{x+2010}{2007}-\dfrac{x+2010}{2000}-\dfrac{x+2010}{1999}-\dfrac{x+2010}{1998}=0\)

\(\Rightarrow\left(x+2010\right).\left(\dfrac{1}{2009}+\dfrac{1}{2008}+\dfrac{1}{2007}-\dfrac{1}{2000}-\dfrac{1}{1999}-\dfrac{1}{1998}\right)\)\(\Rightarrow x+2010=0\)

\(\Rightarrow x=-2010\)

liêm đăng cmt