72^2+144.28+28^2=(72+28)2=1002=10000
Học tốt!!!!!!!!!!
= (x2-2x+1)+4
=(x-1)2+4\(\ge\)4
Dấu "=" xảy ra khi x=1
Vậy......................
\(=\left(x+\frac{1}{2}\right)^2+\frac{1}{2}\ge\frac{1}{2}\)
Dấu "=" xảy ra khi \(x=\frac{-1}{2}\)
Vậy................................................
Mình làm phần còn lại ha
\(85.75=\left(80+5\right)\left(80-5\right)=80^2-5^2=6375\)
\(C=4x^2+5x-3=\left(4x^2+5x+\frac{25}{16}\right)-\frac{73}{16}=\left[\left(2x\right)^2+2.2x.\frac{5}{4}+\left(\frac{5}{4}\right)^2\right]-\frac{73}{16}\)
\(C=\left(2x+\frac{5}{4}\right)^2-\frac{73}{16}\ge\frac{-73}{16}\)
Vậy \(GTNN_C=\frac{-73}{16}\)tại \(x=\frac{-5}{8}\)
A = x2 - 2x + 5
Ta có: A = x2 - 2x + 5 = (x2 - 2x + 1) + 4 = (x - 1)2 + 4
Ta luôn có : (x - 1)2 \(\ge\)0 \(\forall\)x
=> (x - 1)2 + 4 \(\ge\) 4\(\forall\)x
hay A \(\ge\) 4 \(\forall\)x
Dấu "=" xảy ra <=> (x - 1)2 = 0 <=> x - 1 = 0 <=> x = 1
Vậy Amin = 4 tại x = 1
*) B = x2 + x + 1
Ta có: B = x2 + x + 1 = (x2 + x + 1/4) + 3/4 = (x + 1/2)2 + 3/4
Ta luôn có: (x + 1/2)2 \(\ge\)0 \(\forall\)x
=> (x + 1/2)2 + 3/4 \(\ge\) 3/4 \(\forall\)x
hay A \(\ge\)3/4 \(\forall\)x
Dấu "=" xảy ra <=> (x + 1/2)2 = 0 <=> x + 1/2 = 0 <=> x = -1/2
Vậy Bmin = 3/4 tại x = -1/2
\(85.75=\left(80+5\right)\left(80-5\right)=80^2-5^2=6400-25=6375\)
\(72^2+144.28+28^2=72^2+2.72.28+28^2=\left(72+28\right)^2=100^2=10000\)