Question

Tính nhanh hộ mình nhé:

\(\left(1999x1998+1998x1997\right)x\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)

 

Answer 1

\((1999x1998+1998x1997)x(1+\frac{1}{2}\)\(:1\frac{1}{2}\)\(-1\frac{1}{3}\)\()\)
= \((1999x1998+1998x1997)x\)\((1+\frac{1}{2}\)\(:\frac{3}{2}\)\(-\frac{4}{3}\)\()\)
= \((1999x1998+1998x1997)x\)\((1+\frac{1}{3}\)\(-\frac{4}{3}\)\()\)
= \((1999x1998+1998x1997)x\)\((\frac{4}{3}-\frac{4}{3}\)\()\)
=\((1999x1998+1998x1997)x\)0
= 0
Chúc bạn học tốt!

Answer 2

Ta có:

\((1999x1998+1998x1997)x(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3})\)

\(=(1999x1998+1998x1997)x\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)

\(=\left(1999x1998+1998x1997\right)x\left(1+\frac{1}{3}-\frac{4}{3}\right)\)

\(=\left(1999x1998+1998x1997\right)x\left(\frac{4}{3}-\frac{4}{3}\right)\)

\(=\left(1999x1998+1998x1997\right)x0=0\)