a) \(\left(4\dfrac{2}{5}+2\dfrac{3}{7}\right)-\left(2\dfrac{2}{5}-5\dfrac{4}{7}\right)\)
\(=\left(\dfrac{22}{5}+\dfrac{17}{7}\right)-\left(\dfrac{12}{5}-\dfrac{39}{7}\right)\)
\(=\left(\dfrac{22}{5}-\dfrac{12}{5}\right)+\left(\dfrac{17}{7}+\dfrac{39}{7}\right)\)
\(=2+8=10\)
\(b,\left(10\dfrac{3}{8}-3\dfrac{4}{5}\right)+\left(4\dfrac{5}{8}-1\dfrac{1}{5}\right)\)
\(=\left(\dfrac{83}{8}-\dfrac{19}{5}\right)+\left(\dfrac{37}{8}-\dfrac{6}{5}\right)\)
\(=\left(\dfrac{83}{8}+\dfrac{37}{8}\right)-\left(\dfrac{19}{5}+\dfrac{6}{5}\right)\)
\(=15-5=10\)