Question

Tính giá trị các biểu thức sau

a) 9,48-3,42

b) (-0,25):\(\left(\dfrac{1}{2}\right)^2\)

c)\(15.1\dfrac{2}{5}+\dfrac{3}{5}.15\)

d) 0,(123) + \(\dfrac{292}{333}\)

Answer 1

a) \(9\cdot48-3\cdot42=3.3.48-3\cdot42\)

\(=3\left(144-42\right)=3\cdot102=306\)

b) \(\left(-0,25\right):\left(\dfrac{1}{2}\right)^2=\left(-\dfrac{1}{4}\right):\left(\dfrac{1}{4}\right)=\dfrac{-1}{4}.4=-1\)

c) \(15\cdot1\dfrac{2}{5}+\dfrac{3}{5}\cdot15=15\left(\dfrac{7}{5}+\dfrac{3}{5}\right)=15.2=30\)

d) \(0,\left(123\right)+\dfrac{292}{333}=\dfrac{41}{333}+\dfrac{292}{333}=\dfrac{333}{333}=1\)