1.
\(B=20182018.2017-20172017.2018\)
\(B=2018.10001.2017-2017.10001.2018\)
\(B=0\)
1 B=20182018.2017-20172017.2018
B=2018.10001.2017-2017.10001.2018
B=0
2 C=12+22+32+...+1002
C=1(1+0)+2(1+1)+3(1+2)+...+100(1+99)
C=1+2+1.2+3+2.3+...+100+99.100
C=(1+2+3+...+100)+(1.2+2.3+...+99.100)
C=[(1+100).100:2]+[(99.100.101):3]
C=5050+333300
C=338350
1) \(B=20182018.2017-20172017.2018\)
\(B=2018.10001.2017-2017.10001.2018\)
\(B=0-0\)
\(B=0\)
3) \(D=\left(3.4.2^{16}\right)^2:11.2^{13}.4^{11}-16^9\)
\(D=3^2.2^4.2^{32}:11.2^{13}.2^{22}-2^{36}\)
\(D=3^2.2^{71}:11-2^{36}\)
\(D=2^{36}.\left(9.11.2^{35}-1\right)\)