Question

tính giá trị biểu thức :A=3/1.6+3/6.11+......................+3/96.101

Answer 1

\(A=\frac{3}{5}.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{96}-\frac{1}{101}\right)\)

\(A=\frac{3}{5}.\left(1-\frac{1}{101}\right)\)

\(A=\frac{3}{5}.\frac{100}{101}\)

\(A=\frac{60}{101}\)

Answer 2

A = 3 - 3/6 + 3/6 - 3/11 + ... + 3/96 - 3/101

A= 3 - 3/101 

A= 300/101

Answer 3

A=\(3.\left(\frac{1}{1.6}\right)+\left(\frac{1}{6.11}\right)+...+\left(\frac{1}{96.101}\right)\)

5A=\(3.\left(\frac{5}{1.6}\right)+\left(\frac{5}{6.11}\right)+...+\left(\frac{5}{96.101}\right)\)

5A=3. \(\left(1-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{11}\right)+...+\left(\frac{1}{96}-\frac{1}{101}\right)\)

5A=3.(1-\(\frac{1}{101}\))

5A=3.\(\frac{100}{101}\)

5A=\(\frac{300}{101}\) suy ra A= \(\frac{300}{101}:5\)=\(\frac{60}{101}\)