\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\Rightarrow\frac{x^2}{2}-\frac{x}{x}=\frac{1}{6}\)
\(\Rightarrow\frac{x^2}{2}-1=\frac{1}{6}\Rightarrow\frac{x^2}{2}=\frac{1}{6}+1=\frac{7}{6}\)
\(\Rightarrow x^2=\frac{7}{6}.2=\frac{7}{3}\)
\(\Rightarrow x=1.5275252317\)
\(\text{Mình nhầm :}\)
\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\Rightarrow\frac{x^2}{2}-\frac{x}{x}=\frac{1}{6}\)
\(\Rightarrow\frac{x^2}{2}-1=\frac{1}{6}\Rightarrow\frac{x^2}{2}=\frac{1}{6}+1=\frac{7}{6}\)
\(\Rightarrow x^2=\frac{7}{6}.2=\frac{7}{12}\)
\(\Rightarrow x = 0.76376261583\)
x/2-1/x=1/12
x.x-2/2x=1/12
12x2-24=2x
12x2-2x-24=0
x2-x/6=2
x2-x/6+1/144=2+1/144
(x-1/12)2=289/144
x-1/12=\(\pm17\)/12
nếu x-1/12=-\(17\)/12
x=-4/3
nếu x-1/12=17/12
x=3/2
vậy x=3/2 và -4/3