Tính:
\(\frac{45\cdot16-17}{45\cdot15+28}\)
\(=\frac{45\cdot15+45-17}{45\cdot15+28}\)
\(=\frac{45\cdot15+28}{45\cdot15+28}=1.\)
Tìm x:
\(5^x+5^{x+2}=650\)
=>\(5^x+5^x\cdot25=650\)
=>\(5^x\cdot26=650\)
Dễ rồi nhá.
Bài 1 : Ta có : \(\frac{45.16-17}{45.15+28}=\frac{45.16-17}{45.15+45-17}=\frac{45.16-17}{45\left(15+1\right)-17}=\frac{45.16-17}{45.16-17}=1\)
Bài 2 :
Ta có 5x + 5x + 2 = 650
=> 5x(1 + 52) = 650
=> 5x . 26 = 650
=> 5x = 650 : 26
=> 5x = 25
=> 5x = 52
=> x = 2