`@` `\text {Ans}`
`\downarrow`
`5,`
Ta có:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}\Rightarrow\dfrac{x}{3}=\dfrac{2y}{10}=\dfrac{3z}{18}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{3}=\dfrac{2y}{10}=\dfrac{3z}{18}=\dfrac{x-2y+3z}{3-10+18}=\dfrac{-33}{11}=-3\)
\(\Rightarrow\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=-3\)
\(\Rightarrow\left\{{}\begin{matrix}x=-3\cdot3=-9\\y=-3\cdot5=-15\\z=-3\cdot6=-18\end{matrix}\right.\)
Vậy, `x = -9; y = -15; z = -18.`