Các câu hỏi tương tự
Tinh :
A=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)......\left(1+\frac{1}{2014.2016}\right)\)
Giup minh trinh bay ca cach lam nua nha!
Ai chua doc het de va ko hieu thi vao phan "Doc them" se ro
Thanks
tinh:
\(3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{100}}\)
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
trinh bay cach lam nua nhe
Chung minh:
\(\frac{n\left(n+1\right)}{2}\) va 2n+1 nguyen to cung nha voi moi n thuoc N
helps me
Neu ai doc ko het thi vao phan doc them thi se hieu ro hon nhe
Tinh:
\(B=\frac{\frac{1}{7}+\frac{1}{23}-\frac{1}{1009}}{\frac{1}{7}+\frac{1}{23}-\frac{1}{1009}+\frac{1}{7}.\frac{1}{23}.\frac{1}{1009}}\)
Trinh bay cach lam nua nhe
Co gi ko hieu thi vao phan doc them
Tinh:
\(\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
Giup minh trinh bay cach cach giai voi nhe
Ko hieu vao phan"Doc them"
tinh
C=\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)+....+\left(1+\frac{1}{2014.2016}\right)\)
A\(A=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)........\left(1+\frac{1}{2014.2016}\right)\)
Tính A=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{99.101}\right)\)
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)