x-y-z=0=>x=y+z
=>z=x-y;=>y=x-z
\(=>B=\left(1-\frac{z}{x}\right)\left(1-\frac{x}{y}\right)\left(1-\frac{y}{z}\right)=\left(1-\frac{x-y}{x}\right)\cdot\left(1-\frac{y+z}{y}\right)\cdot\left(1+\frac{x-z}{z}\right)\)
Câu a cậu ghi sai đầu bài rồi hay sao í! phải là \(\frac{6}{36.46}\) chứ
Ta có x-y-z=0 suy ra x=z+y;y=x-z;-z=y-x
B=(1-z/x)(1-x/y)(1+y/z)
B=((x-z)/x)((y-x)/y)((z+y)/z)
B=(y/x)(-z/y)(x/z)
B=(-z.y.x)/(z.y.x)
B=-1