\(A=\frac{1}{3}-\frac{3}{4}-\frac{-3}{5}+\frac{1}{73}-\frac{1}{26}+\frac{1}{15}+\frac{-2}{9}\)
\(\Rightarrow A=\left(\frac{1}{3}-\frac{-3}{5}+\frac{1}{15}\right)-\frac{3}{4}+\frac{1}{73}-\frac{1}{26}+\frac{-2}{9}\)
\(\Rightarrow A=\left(\frac{5}{15}-\frac{-9}{15}+\frac{1}{15}\right)-\frac{39}{52}-\frac{2}{52}+\frac{1}{73}+\frac{-2}{9}\)
\(\Rightarrow A=\left(\frac{5}{15}+\frac{9}{15}+\frac{1}{15}\right)-\left(\frac{39}{52}+\frac{2}{52}\right)+\frac{9}{657}+\frac{-146}{657}\)
\(\Rightarrow A=1-\frac{41}{52}+\frac{-137}{657}=\frac{11}{52}+\frac{-137}{657}=\frac{7227}{34164}+\frac{-7124}{34164}=\frac{103}{34163}\)
Vậy \(A=\frac{103}{34164}\)
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