Các câu hỏi tương tự
tim x,y,z khi
\(\frac{x}{7}=\frac{y}{3}va\)x-24=y
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{2}\)va y-x=48
\(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\)va x-y- z=28
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}\)va 2x+3-z=-14
Tim x,y va z neu \(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
tìm x , y , z biết : \(\frac{x}{x+z-5}=\frac{y}{x+z+3}=\frac{z}{x+y+2}=\frac{1}{2}\left(x+y+z\right)\)
Tim x , y , z biet:
\(\frac{x}{y+z+1}=\frac{y}{z+x+2}=\frac{z}{x+y+3}=x+y+z\)
Tìm x, y, z biết: \(\frac{x}{y+z-5}=\frac{y}{x+z+3}=\frac{z}{x+y+2}=\frac{1}{2}\left(x+y+z\right)\)
Tìm x,y,z biết
\(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
Tim ba so x, y, z biet \(\frac{y+z+1}{x}=\frac{x+ z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
biết 3(x+y)=2(y+z)=5(z+x) cm z-x\(\text{biết 3(x+y)=2(y+z)=5(z+x) cm \frac{z-x}{5}=\frac{y-2}{4}}\)
Tìm x,y,z biết:
\(\frac{x+y+3}{z}=\frac{y+z-5}{x}=\frac{x+z+2}{y}=2\left(x+y+z\right)\)