\(\left(x-1\right)\left(2y+3\right)=1\cdot26=26\cdot1=2\cdot13=13\cdot2\)
Ta co bang sau:
| x-1 | 1 | 26 | 2 | 13 | ||||
| 2y+3 | 26 | 1 | 13 | 2 | ||||
| x | 2 | 27 | 3 | 14 | ||||
| y | 11.5 (loai) | -1(loai) | 5 | -0.5(loai) |
tim x,y thuoc N biet (x-6).(2y+3)=8
tim x y thuoc n biet
xy+3x-2y=16
tim x, y thuoc z biet xy-x+2y=3
Tim x,y thuoc Z biet
a}[x-3].[2y+1]=7
b}[2x+1].[3y-2]=-55
tim x,y thuoc Z biet
|y|.|2x+3|=8
|2x+4|+|y-3|=0
|x-1|+|2y+7|=3
|x+5|+|2y+6| nho hon hoac bang 0
tim x;y (la STN) biet(x-2).(2y-3)=26
(2x-1)(3y-2)=27 tim x y biet x y thuoc n
Cho x thuoc {-3;-2;-1;2;3;4;5},y thuoc {-3;-1;0;1;2;3} biet x+ y = 2 tim x, y
Tim x va y thuoc Z, biet:
xy - x + 2y = 3 ghi cach lam nua nhe!
Ai nhanh nhat; dung nhat like lun!!!!!!
