Question

Tìm x:

\(\left(x+\frac{1}{4}-\frac{1}{3}\right)\div\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)

Answer 1

x=3/8

Answer 2

\(\left(x+\frac{1}{4}-\frac{1}{3}\right)\div\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)

\(\Leftrightarrow\left(x+\frac{1}{4}-\frac{1}{6}\right)\div\frac{23}{12}=\frac{7}{46}\)

\(\Leftrightarrow x+\frac{1}{4}-\frac{1}{6}=\frac{7}{46}\times\frac{23}{12}\)

\(\Leftrightarrow x+\frac{1}{4}-\frac{1}{6}=\frac{7}{24}\)

\(\Leftrightarrow x+\frac{1}{4}=\frac{7}{24}+\frac{1}{6}\)

\(\Leftrightarrow x+\frac{1}{4}=\frac{11}{24}\)

\(\Leftrightarrow x=\frac{11}{24}-\frac{1}{4}\)

\(\Leftrightarrow x=\frac{5}{24}\)

Học tốt !

Answer 3

3/8 mới đúng nha bạn

Answer 4

\(\left(x+\frac{1}{4}-\frac{1}{3}\right)\div\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)

\(\left(x+\frac{-1}{12}\right)\div\left(2+\frac{2}{12}-\frac{3}{12}\right)=\frac{7}{46}\)

\(\left(x+\frac{-1}{12}\right)\div\left(2+\frac{-1}{12}\right)=\frac{7}{46}\)

\(\left(x+\frac{-1}{12}\right)\div\frac{23}{12}=\frac{7}{46}\)

\(x+\frac{-1}{12}=\frac{7}{46}.\frac{23}{12}\)

\(x+\frac{-1}{12}=\frac{7}{24}\)

\(x=\frac{7}{24}+\frac{-1}{12}\)

\(x=\frac{3}{8}\)

Vậy  \(x=\frac{3}{8}\)