\(\frac{98}{99}+3-3x=\frac{12}{49}\)
\(-3x=\frac{12}{49}-\frac{98}{99}-3=-\frac{3614}{4851}-3=-\frac{18167}{4851}\Leftrightarrow x=-\frac{18167}{14553}\)
Tìm x:
\(\frac{98}{99}\) + 3 - 3x = \(\frac{192}{49}\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
tim x
Tính \(T=\left(\frac{2}{98}+\frac{3}{97}+...+\frac{99}{1}\right)X\left(\frac{1}{99}+\frac{2}{98}+...+\frac{98}{2}\right)-\left(\frac{1}{99}+\frac{2}{98}+..+\frac{99}{1}\right)X\left(\frac{2}{98}+\frac{3}{97}+...+\frac{98}{2}\right)\)
Tính: \(B=\frac{100^2+1^2}{100\cdot1}+\frac{99^2+2^2}{99\cdot2}+\frac{98^2+3^2}{98\cdot3}+...+\frac{52^2+49^2}{52\cdot49}+\frac{51^2+50^2}{51\cdot50}\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}=\frac{x+10}{90}+\frac{x+11}{89}+\frac{x+12}{88}\)
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)\(\frac{1}{95}\)
\(Bài1:x+y=\frac{1}{2},y+z=\frac{1}{3},z+x=\frac{1}{4}\)
\(Bai2:\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)
Bài 1 : Tìm x
1) \(\frac{x-1}{10}\) + \(\frac{x-1}{11}\)+\(\frac{x-1}{12}\)-\(\frac{x-1}{13}\)= 0
2 ) \(\frac{x-1}{99}\)+\(\frac{x-2}{98}\)+\(\frac{x-5}{95}\)= 3 + \(\frac{1}{99}\)+\(\frac{1}{98}\)+\(\frac{1}{95}\)
tim x E Z biet
\(a,\frac{2x-12}{x-3}=\frac{x-3}{2x-12}\)
\(b,\frac{3x+4}{x-16}=\frac{x-16}{3x+4}\)
