cho mình bỏ đi 1 phân số \(\frac{x}{45}\)ở cuối nhé
cho mình bỏ đi 1 phân số \(\frac{x}{45}\)ở cuối nhé
TÍNH
\(\frac{1+0,6-\frac{3}{7}}{\frac{8}{3}+\frac{8}{5}-\frac{8}{7}}-\frac{\frac{1}{3}+0,25-\frac{1}{5}+0,125}{\frac{7}{6}+\frac{7}{8}-0,7+\frac{7}{16}}\)
TÌM X
a) \(\frac{59-x}{41}+\frac{57-x}{43}+\frac{55-x}{45}+\frac{53-x}{47}+\frac{51-x}{49}=-5\)
b) \(\frac{x-5}{1990}+\frac{x-15}{1980}+\frac{x-25}{1970}=\frac{x-1990}{5}+\frac{x-1980}{15}+\frac{x-1570}{25}\)
CÁC BẠN GIÚP MK NHÉ! CẢM ƠN CÁC BẠN NHÌU NHA!
Tìm x, biết:
\(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)
\(\frac{x+29}{31}-\frac{x +17}{33}=\frac{x+17}{43}-\frac{x+15}{45}\)
Tính các tổng sau:
\(C=\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
Tìm x
\(x-\frac{3}{10}=\frac{5}{7}\)
\(x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)
\(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\)
\(1-x=\frac{49}{65}.\frac{5}{7}\)
\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=\frac{-37}{45}\)
Tính hợp lý giá trị của biểu thức sau:
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(B=71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)
\(D=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
tìm x, biết:
\(\left(\frac{5}{12}+\frac{-5}{7}+\frac{-22}{45}+\frac{7}{12}+\frac{-23}{45}\right).\)I x I -9 = - 2
Tìm x
a, \(\frac{x}{2}+\frac{x}{3}+\frac{x}{5}-\frac{1}{3}=\frac{2}{15}\)
b, x + 2 + x +3 + x +5 = 28
c, { x + 1 } + { x + 2 } + .........+ { x + 9 } = 45
tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
Tính nhanh:
M=\(\frac{-7}{9}.\frac{15}{49}.\frac{9}{7}.15.\frac{14}{15}\)
N=\(\frac{5}{9}.\frac{4}{7}.\frac{10}{3}+\frac{15}{45}.\frac{3}{7}.\frac{1}{2}\)