\(8x\left(x-2017\right)-2x+4034=0\)\(\Leftrightarrow8x\left(x-2017\right)-2\left(x-2017\right)=0\)
\(\Leftrightarrow2\left(x-2017\right)\cdot\left(4x-1\right)=0\)\(\Leftrightarrow\hept{\begin{cases}x-2017=0\\4x-1=0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=2017\\x=\frac{1}{4}\end{cases}}\)
Vậy \(x=2017\)hoặc \(x=\frac{1}{4}\)
8x( x - 2017 ) - 2x + 4034 = 0
<=> 8x( x - 2017 ) - 2( x - 2017 ) = 0
<=> ( 8x - 2 )( x - 2017 ) = 0
<=> \(\orbr{\begin{cases}8x-2=0\\x-2017=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=2017\end{cases}}\)
2 8
