\(\left(x-\frac{1}{5}\right)^2=\frac{1}{25}\)
\(\Leftrightarrow x-\frac{1}{5}=\frac{1}{5}\)
\(\Rightarrow x=\frac{2}{5}\)
P/s tham khảo nha
\(\left(\frac{3}{2}-x\right)^3=-8\)
\(\Leftrightarrow\frac{3}{2}-x=-2\)
\(\Rightarrow x=\frac{7}{2}\)
P/s tham khảo nha
\(\left(x-\frac{1}{5}\right)^2=\left(\frac{1}{5}\right)^2=\left(-\frac{1}{5}\right)^2\)
\(\orbr{\begin{cases}x-\frac{1}{5}=\frac{1}{5}\\x-\frac{1}{5}=-\frac{1}{5}\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{2}{5}\\x=0\end{cases}}\)
Vậy...
b)\(\left(\frac{3}{2}-x\right)^3=-2^3\)
\(\frac{3}{2}-x=-2\)
\(x=\frac{3}{2}+2\)
\(x=\frac{7}{2}\)
a) \(\left(x-\frac{1}{5}\right)^2=\frac{1}{25}\)
Ta có: \(\frac{1}{25}=\pm\left(\frac{1}{5}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{5}=\frac{1}{5}\\x-\frac{1}{5}=\frac{-1}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=0\end{cases}}}\)
Vậy x = 0 hoặc x = 2/5
b) Ta có: \(\left(-2\right)^3=-8\)
\(\Rightarrow\left(\frac{3}{2}-x\right)^3=\left(-2\right)^3\)
\(\Rightarrow\frac{3}{2}-x=-2\)
\(\Rightarrow x=\frac{3}{2}-\left(-2\right)=\frac{7}{2}\)
Vậy x = 7/2
a) \(\left(x-\frac{1}{5}\right)^2=\left(\frac{1}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{5}=\frac{1}{5}\\x-\frac{1}{5}=-\frac{1}{5}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=0\end{cases}}}\)
b)\(\left(\frac{3}{2}-x\right)^3=-2^3\)
\(\Leftrightarrow\frac{3}{2}-x=-2\Leftrightarrow x=\frac{7}{2}\)
a) (x - 0,2 )2 = 0,04
( x - 0,2)2 = 0,22 ( vì 0,2 x 0,2 = 0,04)
Suy ra x - 0,2 = 0,2
x = 0,2 + 0,2
x = 0,4
b, ( 1,5 - x )3 = -8
( 1,5 - x )3 = -23
Suy ra 1,5 - x = -2
x = 1,5 - (-2)
x = 3,5
