Question

Tìm x:

a) \(\frac{x+1}{2011}+\frac{x+1}{2012}=\frac{x+1}{2013}+\frac{x+1}{2014}\)

b)\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)

c)\(2.\left(x-\frac{1}{3}\right)-5.\left(x-\frac{1}{4}\right)=4x\)

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Answer 1

A)=>x + 1/2011+ x + 1/2012 - x + 1/2013 - x + 1/2014 =0

<=>(x + 1) . ( 1/2011+ 1/2012-1/2013 - 1/2014) = 0

=>x + 1 = 0 (vì 1/2011+ 1/2012 - 1/2013 - 1/2014 khác 0)

=>x     =  -1

vậy x   =  -1

B)x-100/24+x-98/26+x-96/28=3

<=>x - 100/24 - 1 + x - 98/26 - 1 + x - 96/28 =0

<=>x - 124/24 + x - 124/26 + x - 124/28 = 0

<=>(x-124).( 1/24 + 1/26 + 1/28 ) = 0

mà 1/24 + 1/26 +1/28 khác 0

=>x - 124 = 0

<=>x       = 124