Question

\(tìm\) \(x\)

\(4-\left(\dfrac{4x}{2x}+\dfrac{4x}{2\left(x+3\right)}\right)=\dfrac{1}{3}\)

 

 

 

 

Answer 1

ĐKXĐ: \(x\notin\left\{0;-3\right\}\)

\(4-\left(\dfrac{4x}{2x}+\dfrac{4x}{2\left(x+3\right)}\right)=\dfrac{1}{3}\)

=>\(4-\left(2+\dfrac{2x}{x+3}\right)=\dfrac{1}{3}\)

=>\(2-\dfrac{2x}{x+3}=\dfrac{1}{3}\)

=>\(\dfrac{2x}{x+3}=2-\dfrac{1}{3}=\dfrac{5}{3}\)

=>\(2x\cdot3=5\left(x+3\right)\)

=>6x=5(x+3)

=>6x=5x+15

=>x=15(nhận)