Question

tìm x, y

\(a.\left(x-5\right)^2=\left(1-3x\right)^2\)

\(b.\left(x+5\right)^2+\left(3y-9\right)^4=0\)

\(c.\frac{1}{8}.16^x=2^x\)

\(d.2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

Answer 1

chịch ko

Answer 2

\(a,\left(x-5\right)^2=\left(1-3x\right)^2\)

\(\Rightarrow\left(x-5\right)^2-\left(1-3x\right)^2=0\)

\(\Rightarrow\left(x-5+1-3x\right)\left(x-5-1+3x\right)=0\)

\(\Rightarrow\left(-2x-4\right)\left(4x-6\right)=0\)

\(\Rightarrow\left(x+2\right)\left(2x-3\right)=0\)

\(\Rightarrow\hept{\begin{cases}x+2=0\\2x-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=-2\\x=\frac{3}{2}\end{cases}}}\)

Answer 3

a) \(\left(x-5\right)^2=\left(1-3x\right)^2\)

\(\Rightarrow x-5=1-3x\)

\(\Leftrightarrow x+3x=1+5\)

\(\Leftrightarrow4x=6\)

\(\Leftrightarrow x=\frac{3}{2}\)

Answer 4

a) \(\left(x-5\right)^2=\left(1-3x\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x-5=1-3x\\x-5=3x-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}4x=6\\-2x=4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-2\end{cases}}\)

Answer 5

\(\frac{1}{8}.16^x=2^x\)

\(\frac{16^x}{2^x}=8\)

\(\left(\frac{16}{2}\right)^x=8\)

\(8^x=8\)

\(\Rightarrow x=1\)