\(\left(x-1\right)\left(x^2+1\right)=0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
\(\left(x^2-1\right)\left(49-x^2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2-1=0\\49-x^2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=7\end{cases}}}\)
Tim x thuoc Z
1/ x(x+3)=0
2/ (x-2)(5-x)=0
3/(x-1)(x2+1)=0
tim x thuoc z
(x2+7).(x2-49)<0
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100tim x , y thuoc Z
|x+2|.|y-1|-4|y-1|=0
|x-2|+|(x-2).(y+5)|=0
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0
Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
a/[x-2][7-x] > 0 . tim x thuoc Z
b/[x mu 2+13][x mu 2-17] > 0 . tim x thuoc Z
c/[x mu 2-13][x mu 2-17] <0 . tim x thuoc Z
GIUP MINH VOI
NGAY KIA MINH DI BOI DUONG ROI
CAM ON CAC BAN NEU CAC BAB GIUP MINH
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
Giup mink cau nay nha
1,chung minh dang thuc
-(-a+b+c)+(b-c-1)=(b-c+6)-(7-a+b)+c
2,Tim x thuoc Z
(x+1)+(x+3)+(x+5)+.....+(x+99)=0
(x-3)+(x-2)+(x-1)+...+10+11=0
