Question

Tìm x, biết

\(a,5x+2\frac{4}{5}=15\)

b, \(x-105:3=-23\)

c,\(\frac{2}{5}x+20\%x=\frac{6}{5}\)

Giúp mình, ai nhanh mình tick

Answer 1

a. 5x +2 4/5 = 15

=> 5x + 14/5 = 15

=> 5x = 15 - 14/5 = 61/5

=> x = 61/5 : 5 

=> x = 61/25

Answer 2

a)5x + 2 4/5 =15

5x+14/5=15

5x=15- 14/5

5x=71/5

x=71/5 :5

x=71

Answer 3

X-105:3=-23

X-35=-23

x=-23+(-35)

x=-88

Answer 4

b. x - 105 : 3 = - 23

=> x - 35 = - 23

=> x = - 23 + 35 

=> x = 12

Answer 5

c. 2/5x + 20%x = 6/5

=> 2/5x + 1/5x = 6/5

=> 3/5x = 6/5

=> x = 6/5 : 3/5

=> x = 2

Answer 6

c)2/5x + 20% x=6/5

x.(2/5+1/5)=6/5

x.3/5=6/5

x=6/5:3/5

x=2

Answer 7

A) 5x+ 2 4/5=15

5x +14/5=15

5x. =15-14/15

5x. =61/5

5x. =61/5:5

  x. =2.44 hoặc 61/25

B) x-105:3=-23

     x -35 =-23

     x =-23+35

      X =12

C) 2/5x+20%x=6/5

       2/5x+1/5x=6/5

=> 3/5x=6/5

=> x=6/5:3/5

=> x=2

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