\(\frac{3x-5}{x+4}=\frac{5}{2}\)
=> 2(3x - 5) = 5(x + 4)
=> 6x - 10 = 5x + 20
=> 6x - 5x = 20 + 10
=> x = 30
ĐKXĐ: \(x\ne-4\)
\(\frac{3x-5}{x+4}=\frac{5}{2}\)
\(\Rightarrow5\left(x+4\right)=2\left(3x-5\right)\)
=> 5x + 20 = 6x - 10
=> x = 30
\(\frac{3x-5}{x+4}=\frac{5}{2}\)
\(\Rightarrow2\left(3x-5\right)=5\left(x+4\right)\)
\(\Rightarrow6x-10=5x+20\)
\(\Rightarrow6x-5x=20+10\)
\(\Rightarrow x=30\)