Question

Tìm x biết: \(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

 

Answer 1

=>4x+(1/2+1/4+1/8+1/16)=1

<=>4x+15/16=1

=>4x=1/16

=>x=1/16:4=1/64

vậy x=1/64

 

Answer 2

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

\(\Rightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(\Rightarrow4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)

\(\Rightarrow4x+\left(1-\frac{1}{16}\right)=1\)

\(\Rightarrow4x+\frac{15}{16}=1\)

\(\Rightarrow4x=1-\frac{15}{16}\)

\(\Rightarrow x=\frac{1}{16}:4\)

\(\Rightarrow x=\frac{1}{64}\)

vậy \(x=\frac{1}{64}\)