Ta có :
\(a)\)\(2\left(5-x\right)-7\left(x-2\right)=-3\)
\(\Leftrightarrow\)\(10-2x-7x+14=-3\)
\(\Leftrightarrow\)\(-2x-7x=-3-10-14\)
\(\Leftrightarrow\)\(-9x=-27\)
\(\Leftrightarrow\)\(x=\frac{-27}{-9}\)
\(\Leftrightarrow\)\(x=3\)
Vậy \(x=3\)
a) 2(5 - x) - 7(x - 2) = -3
10 - 2x - 7x + 14 = -3
24 - 9x = -3
9x = 24 + 3
9x = 27
x = 3
b) 12 \(⋮\)x, 8 \(⋮\)x và x nhỏ hơn 0
Vì \(12⋮x\), \(8⋮x\)và x < 0 => x \(\in\)ƯC(12; 8) và x thuộc z
Ta có : 12 = 22 . 3
8 = 23
ƯCLN(12; 8) = 22 = 4
ƯC(12;8) = Ư(4) = {-1;1; -2; 2; -4 ; 4}
Vì x < 0 nên x = {-1; -2; -4}
a) \(2\left(5-x\right)-7\left(x-2\right)=-3\)
\(10-2x-7x+14=-3\)
\(-9x+24=-3\)
\(-9x=-3-24\)
\(-9x=-27\)
\(x=3\)
\(2\left(5-x\right)-7\left(x-2\right)=-3\)
\(2\cdot5-2x-7x+7\cdot2=-3\)
\(10+14-2x-7x=-3\)
\(24-9x=-3\)
\(9x=24-\left(-3\right)\)
\(9x=27\)
\(x=27:9\)
\(x=3\)
a) \(2\left(5-x\right)-7\left(x-2\right)=-3\)
\(10-2x-7x+14=-3\)
\(10+14-2x-8x=-3\)
\(24-9x=-3\)
\(9x=24-\left(-3\right)\)
\(9x=27\)
\(x=27\div9\)
\(x=3\)
10-2x-7x+14=-3
(10+14)-(2x+7x)=-3
24-x(2+7)=-3
24-9x=-3
9x=24-(-3)
9x=27
x=27:9
x=3
Vậy x=3
