a) \(-7.\left|x-2013\right|+2012^0=\left|+1\right|\)
\(\Leftrightarrow-7.\left|x-2013\right|+1=1\)
\(\Leftrightarrow-7.\left|x-2013\right|=0\)
\(\Leftrightarrow\left|x-2013\right|=0\)
\(\Leftrightarrow x-2013=0\)
\(\Leftrightarrow x=2013\)
Vậy x = 2013
a) -7.|x-2013| + 20120 = |+1|
-7.|x-2013| + 1 = 1
=> -7.|x-2013| = 0
=> | x-2013| = 0
=> x - 2013 = 0
x = 2013
\(-7.\left|x-2013\right|+1=\left|+1\right|\)
\(-7\left|x-2013\right|+1=1\)
\(-7\left|x-2013\right|=1-1\)
\(-7\left|x-2013\right|=0\)
\(\Rightarrow\left|x-2013\right|=0\)
\(\Rightarrow x-2013=0\)
\(x=2013\)
Vậy \(x=2013\)
