Question

tìm x

a, (3x)+(2x+7)=2x

b, \(\dfrac{x+1}{2}\)=\(\dfrac{1}{3}\)

Answer 1

a) \(\left(3x\right)+\left(2x+7\right)=2x\)

\(\Leftrightarrow3x=-7\Leftrightarrow x=-\dfrac{7}{3}\)

Vậy .............

b ) \(\dfrac{x+1}{2}=\dfrac{1}{3}\Leftrightarrow3x+3=2\Leftrightarrow3x=-1\Leftrightarrow x=-\dfrac{1}{3}\)

Vây .......

Answer 2

b, \(\dfrac{x+1}{2}=\dfrac{1}{3}\)

\(\Rightarrow3\left(x+1\right)=2.1\)

\(\Rightarrow x+1=\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{-1}{3}\)