Question

Tim x:

  a/ 3x - \(\frac{3}{2}\)- 5x+ \(\frac{10}{3}\) = 1

  b/ |x-1|= 5-x

 Cac ban mau giai ho minh nha! Mai minh nop bai roi

Answer 1

a) \(3x-\frac{3}{2}-5x+\frac{10}{3}=1\)

\(3x-5x=1+\frac{3}{2}-\frac{10}{3}\)

\(-2x=-\frac{5}{6}\)

\(x=\frac{5}{12}\)

b) \(\left|x-1\right|=5-x\)

Th1:

\(x-1=5-x\)

\(x+x=5+1\)

\(2x=6\)

\(x=3\)

Th2:

\(-\left(x-1\right)=5-x\)

\(x+1=5-x\)

\(x+x=5-1\)

\(2x=4\)

\(x=2\)

Vậy \(x=3\)và \(x=2\)

Answer 2

a) 3x - 5x = 1 + 3/2 - 10/3

-2x = -5/6

x = -5/6 : ( - 2 )

x = 5/12

b)  |x-1|= 5-x

Nếu x \(\ge\)1 \(\Rightarrow\)x - 1 \(\ge\)0 \(\Rightarrow\)x - 1 = 5 - x.

2x = 6

x = 3.

Nếu x < 1 \(\Rightarrow\)x - 1 < 0 \(\Rightarrow\)Ix-1I = 1 - x

\(\Rightarrow\)1 - x = 5 - x \(\Rightarrow\)vô lý.

Vậy x = 3