=>2013= |x-4+10-x+x+101+999-x+x+1000|
rồi cộng lại đc bn + x
rồi chia Th ra
Xét VP = \(\left(\left|x-4\right|+\left|x+999\right|\right)+\left(\left|x-10\right|+\left|x+1000\right|\right)+\left|x+101\right|\)
\(\ge\left|x+999+4-x\right|+\left|x+1000+10-x\right|+\left|x+101\right|\)
\(=2013+\left|x+101\right|\ge2013=VT\)
=> VP \(\ge\)VT
Dấu "=" xảy ra <=>\(\hept{\begin{cases}\left(x+999\right)\left(4-x\right)\ge0\\\left(x+1000\right)\left(10-x\right)\ge0\\x+101=0\end{cases}}\)<=> x = -101
Vậy VP = VT <=> x = -101