Question

tìm giá trị của biểu thức sau: \(\frac{2^7.9^3}{6^5.8^2}\)

Answer 1

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)

Answer 2

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3.3\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^3.3^3}{2^5.3^5.2^6}=\frac{3}{16}\)

Answer 3

27.9365.82=27.(32)3(2.3)5.(23)2=27.3625.35.26=27.36211.3527.9365.82=27.(32)3(2.3)5.(23)2=27.3625.35.26=27.36211.35=324=316

Answer 4

cảm ơn nha