Question

tìm BC ( 12 21 28 )

Answer 1

Ta có :

12 = 2² . 3

21 = 3 . 7

28 = 2² . 7

=> BCNN(12 , 21 , 28) = 2² . 3 . 7 = 84

B(84) = { 0 , 84 , 168 , 252 , 336 , 420 , ... }

=> BC(12 , 21 , 28) = { 0 , 84 , 168 , 252 , 336 , 420 , ... }

Answer 2

12=2².3

21=3.7

28=2².7

BCNN(12;21;28)=2².3.7=84

BC(12;21;28)={0;84;168;252;336;...}

Answer 3

ta có :

12 = 2² . 321= 3 . 7 

28 = 2² . 7

=> BCNN (12,21,28) =2² . 3 . 7 = 84

B(84) = {0,84,168,252,336,420,....}

=> BC ( 12,21,28) = {0,84,168,252,336,420,...}

Answer 4

Ta có:

12=2²*3

21= 3*7

28=2²*7

Answer 5

Ta có:

12 = 2² . 3

21 = 3 . 7

28 = 2² . 7

=> BCNN ( 12, 21, 28 ) = 2² . 3 . 7 = 84

B ( 84 ) = { 84; 168; 252; 336; 420; ... }

Vậy: BC ( 12, 21, 28 ) = { 84; 168; 252; 336; 420; ... }

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