\(\sqrt{2003}\)\(+\)\(\sqrt{2004}\)\(>\)\(2\)\(\sqrt{2004}\)
k mik nha
Đặt \(A^2=\left(\sqrt{2003}+\sqrt{2004}\right)^2>0\)
\(\le\left(1+1\right)\left(2003+2004\right)=2\cdot4007=8014\)
\(\Rightarrow A^2\le8014\). Và
\(B^2=\left(2\sqrt{2004}\right)^2=4\cdot2004=8016\)
Suy ra \(A^2\le8014< 8016=B^2\Leftrightarrow A< B\)