Ta có:\(A=\frac{1}{2.2}+\frac{1}{3.3}+\frac{1}{4.4}+...+\frac{1}{10.10}< \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
Mà \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}< 1\)
=>A<1
\(\text{Ta có: }\frac{1}{2.2}< \frac{1}{1.2};\frac{1}{3.3}< \frac{1}{2.3};.....;\frac{1}{10.10}< \frac{1}{9.10}\)
\(\Rightarrow A< \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{9.10}\)
\(\Rightarrow A< 1-\frac{1}{10}\)
\(\Rightarrow A< \frac{9}{10}< 1\)
A = 1/2.2 + 1/3.3 + 1/4.4 + ... + 1/10.10
A < 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/9.10
A < 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/9 - 1/10
A < 1 - 1/10 < 1
=> A < 1
Ta có: 1/2x2 <1/1x2 ;1/3x3 <1/2x3 ;.....;1/10x10 <1/9x10
⇒A<1,1x2 +1/x3 +1/3x4 +....+1/9x10
⇒A<1−1/10
⇒A<9/10 <1
A = 1/2.2 + 1/3.3 + 1/4.4 + ... + 1/10.10
A < 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/9.10
A < 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/9 - 1/10
A < 1 - 1/10 < 1
=> A < 1
