\(\dfrac{5}{7};\dfrac{6}{11};\dfrac{6}{7};\dfrac{6}{5}\)
\(\dfrac{6}{5}>\dfrac{6}{7}>\dfrac{5}{7}>\dfrac{6}{11}\)
\(\dfrac{6}{5};\dfrac{6}{7};\dfrac{5}{7};\dfrac{6}{11}\)
\(\dfrac{5}{7};\dfrac{6}{11};\dfrac{6}{7};\dfrac{6}{5}\)
\(\dfrac{6}{5}>\dfrac{6}{7}>\dfrac{5}{7}>\dfrac{6}{11}\)
\(\dfrac{6}{5};\dfrac{6}{7};\dfrac{5}{7};\dfrac{6}{11}\)
SẮP SẾP THEO TĂNG DẦN
\(\dfrac{2}{3}\);\(\dfrac{9}{12}\);\(\dfrac{5}{4}\);\(\dfrac{5}{5}\);\(\dfrac{1}{6}\)
Tính theo cách thuận tiện :
\(\dfrac{13}{7}+\dfrac{5}{6}+\dfrac{2}{7}+\dfrac{7}{6}\) = ?
\(\dfrac{1}{2}x\dfrac{5}{6}+\dfrac{1}{2}x\dfrac{11}{6}=?\)
\(\dfrac{6}{7}\) + \(\dfrac{2}{3}\) x \(\dfrac{5}{4}\)
\(\dfrac{9}{5}\) - \(\dfrac{6}{7}\): \(\dfrac{11}{7}\)
405 : 27 x 516
\(\dfrac{6}{7}\) + \(\dfrac{2}{3}\) x \(\dfrac{5}{4}\)
\(\dfrac{9}{5}\) - \(\dfrac{6}{7}\) : \(\dfrac{11}{7}\)
Tính thuận tiện :
\(\dfrac{9}{5}+\dfrac{5}{7}+\dfrac{7}{5}+\dfrac{3}{7}\) = ?
\(\dfrac{1}{2}x\dfrac{45}{33}x\dfrac{1}{9}x\dfrac{11}{6}\) = ?
tính nhanh
\(\dfrac{6}{11}\)+\(\dfrac{2}{5}\)+\(\dfrac{16}{11}\)+\(\dfrac{19}{13}\)+\(\dfrac{3}{5}\)+\(\dfrac{7}{13}\)
Tính
a.\(\dfrac{4}{9}+\dfrac{3}{7}\) \(\dfrac{3}{4}+\dfrac{7}{24}\) \(\dfrac{1}{3}+\dfrac{2}{9}+\dfrac{4}{27}\)
b.\(\dfrac{5}{6}-\dfrac{3}{8}\) \(\dfrac{7}{15}-\dfrac{11}{30}\) \(\dfrac{2}{3}+\dfrac{1}{6}-\dfrac{7}{12}\)
c.\(\dfrac{18}{25}\times\dfrac{15}{6}\) \(\dfrac{30}{49}:\dfrac{6}{7}\) \(\dfrac{1}{2}\times\dfrac{3}{4}:\dfrac{6}{5}\)
d.\(8\times\dfrac{3}{5}:\dfrac{12}{5}\) \(4:\dfrac{9}{5}:\dfrac{10}{3}\)
3 bn đầu tiên xong mik sẽ tick
a \(\dfrac{3}{7}\)+\(\dfrac{3}{4}\)-\(\dfrac{1}{2}\)=
b \(\dfrac{6}{11}\)+\(\dfrac{2}{9}\)x12=
c \(\dfrac{5}{7}\)-\(\dfrac{8}{5}\):4=
Câu 1: Các phân số \(\dfrac{8}{5}\);\(\dfrac{9}{10}\);\(\dfrac{9}{11}\);\(\dfrac{8}{7}\) được sắp xếp theo thứ tự từ lớn đến bé
Câu 2:Viết phân số \(\dfrac{1}{6}\) thành hiệu của hai phân số có tử số bằng 1 :
\(\dfrac{1}{6}\) = \(\dfrac{...}{6}\) - \(\dfrac{...}{6}\) = \(\dfrac{1}{...}\) - \(\dfrac{1}{...}\)